104b^2-75b-14=0

Solution for 104b^2-75b-14=0 equation:

104b^2-75b-14=0

a = 104; b = -75; c = -14;
Δ = b2-4ac
Δ = -752-4·104·(-14)
Δ = 11449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11449}=107$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-107}{2*104}=\frac{-32}{208}
=-2/13
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+107}{2*104}=\frac{182}{208}
=7/8
$